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Quantitative Method QA2-3
發問:
The time to complete a construction project is normally distributed with a mean of 60 weeks and a standard deviation of 4 weeks.a)What is the probability the project will be finished in 62 weeks or less?b)What is the probability the project will be finished in 66 weeks or less?c)What is the probability the... 顯示更多 The time to complete a construction project is normally distributed with a mean of 60 weeks and a standard deviation of 4 weeks. a)What is the probability the project will be finished in 62 weeks or less? b)What is the probability the project will be finished in 66 weeks or less? c)What is the probability the project will take longer than 65 weeks?
(a) 62 weeks is of 0.5 time of standard deviation higher than the mean, therefore the required probability is: P(z < 0.5) = 0.5 + 0.1915 = 0.6915 (b) 66 weeks is of 1.5 time of standard deviation higher than the mean, therefore the required probability is: P(z < 1.5) = 0.5 + 0.4332 = 0.9332 (c) 65 weeks is of 1.25 time of standard deviation higher than the mean, therefore the required probability is: P(z > 1.25) = 0.5 - 0.3944 = 0.1056
其他解答:
Quantitative Method QA2-3
發問:
The time to complete a construction project is normally distributed with a mean of 60 weeks and a standard deviation of 4 weeks.a)What is the probability the project will be finished in 62 weeks or less?b)What is the probability the project will be finished in 66 weeks or less?c)What is the probability the... 顯示更多 The time to complete a construction project is normally distributed with a mean of 60 weeks and a standard deviation of 4 weeks. a)What is the probability the project will be finished in 62 weeks or less? b)What is the probability the project will be finished in 66 weeks or less? c)What is the probability the project will take longer than 65 weeks?
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最佳解答:(a) 62 weeks is of 0.5 time of standard deviation higher than the mean, therefore the required probability is: P(z < 0.5) = 0.5 + 0.1915 = 0.6915 (b) 66 weeks is of 1.5 time of standard deviation higher than the mean, therefore the required probability is: P(z < 1.5) = 0.5 + 0.4332 = 0.9332 (c) 65 weeks is of 1.25 time of standard deviation higher than the mean, therefore the required probability is: P(z > 1.25) = 0.5 - 0.3944 = 0.1056
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