標題:
math 三角比的關係
發問:
化簡: (sin r - cos r) (sin r - cos r) + 2sin r cos r
(sin r - cos r) (sin r - cos r) + 2sin r cos r =(sin r - cos r) ^2+ 2sin r cos r =sin^2r-2sin r cos r +cos^2r+ 2sin r cos r =1
其他解答:
answer is 1 ! http://hk.knowledge.yahoo.com/question/?qid=7007082502243 ←can anyone help me??
math 三角比的關係
發問:
化簡: (sin r - cos r) (sin r - cos r) + 2sin r cos r
此文章來自奇摩知識+如有不便請留言告知
最佳解答:(sin r - cos r) (sin r - cos r) + 2sin r cos r =(sin r - cos r) ^2+ 2sin r cos r =sin^2r-2sin r cos r +cos^2r+ 2sin r cos r =1
其他解答:
answer is 1 ! http://hk.knowledge.yahoo.com/question/?qid=7007082502243 ←can anyone help me??
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