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數學三角學的應用問題
發問:
因小弟在教這課時去了交流,於是沒有聽這一課,希望以下題目可有人教教點做,謝謝~ http://i1233.photobucket.com/albums/ff400/rein1993/9a1e7359.jpg
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其他解答:
數學三角學的應用問題
發問:
因小弟在教這課時去了交流,於是沒有聽這一課,希望以下題目可有人教教點做,謝謝~ http://i1233.photobucket.com/albums/ff400/rein1993/9a1e7359.jpg
最佳解答:
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11. ΔTYZ中: tan∠TZY = TY/YZ tan27° = (3 m)/YZ YZ = 3/tan27° m ΔXYZ中,根據正弦定律: sin∠YXZ/YZ = sin∠YZX/XY sin12°/(3/tan27°) = sin∠YZX/24 sin∠YZX = 8sin12°tan27° ∠YZX = 57.9° 57.9° + 12° = 69.9° 由Z測得T的方位 = S69.9°W = = = = = 14. (a) ΔXBY中: ∠BXY = 90° - 60° = 30° ∠BYX = 90° - 30° = 60° 三角形內角和: ∠XBY + ∠BXY + ∠BYX = 180° ∠XBY + 30° + 60° = 180° ∠XBY = 90° (b) ΔXBY中: sin∠BXY = BY/XY sin30° = BY/(24 km) BY = 24 sin30° km BY = 12 km ΔABY中: tan∠AYB = AB/BY tan10° = AB/(12 km) AB = 12tan10° km AB = 2.1 km (c) ΔXBY中: cos∠BXY = BX/XY cos30° = BX/(24 km) BX = 24cos30° km ΔABX中: tan∠AXB = AB/BX tan∠AXB = (12tan10°)/(24cos30°) ∠AXB = 5.8° 由X測得飛機A之仰角 = 5.8°其他解答:
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