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發問:
如何計算水壓 ? 例如水深為 200 米時，水壓是多少又或者水壓為 23 x 105Pa，水深是幾多 ? 更新: 23 x 10^5 Pa
最佳解答:
Use the simple equation: pressure = h.d.g where h is the height (or depth) of water column d is the density of water (taken to be 1000 kg/m^3) g is the acceleration due to gravity (taken to be 10 m/s^2 for simplicity. But for more accurate calculation, you should use g = 9.81 m/s^2 ) Hence, given a depth of 200m, the pressure = 200 x 1000 x 10 N/m^2 = 2 x 10^6 N/m^2 = 2 x 10^6 Pa If given a pressure of 23 x 10^5 Pa depth of water = 23 x 10^5/(1000 x 10) m = 230 m
其他解答:
Pressure= density x gravity x height ( you should find out the mass or volume or density first.)
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如何計算水壓 ?發問:
如何計算水壓 ? 例如水深為 200 米時，水壓是多少又或者水壓為 23 x 105Pa，水深是幾多 ? 更新: 23 x 10^5 Pa
最佳解答:
Use the simple equation: pressure = h.d.g where h is the height (or depth) of water column d is the density of water (taken to be 1000 kg/m^3) g is the acceleration due to gravity (taken to be 10 m/s^2 for simplicity. But for more accurate calculation, you should use g = 9.81 m/s^2 ) Hence, given a depth of 200m, the pressure = 200 x 1000 x 10 N/m^2 = 2 x 10^6 N/m^2 = 2 x 10^6 Pa If given a pressure of 23 x 10^5 Pa depth of water = 23 x 10^5/(1000 x 10) m = 230 m
其他解答:
Pressure= density x gravity x height ( you should find out the mass or volume or density first.)
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