close
標題:
math help!
發問:
1/a+1/b+1/c=1/8 a=? b=? c=?
1/a + 1/b + 1/c = 1/8 1/a = 1/8 - 1/b - 1/c 1/a = (bc - 8b - 8c) / 8bc a = 8bc / (bc-8b-8c) Similarly, you can get: b = 8ac / (ac-8a-8c) c = 8ab / (ab-8a-8b)
其他解答:
a=16 b=32 c=64
math help!
發問:
1/a+1/b+1/c=1/8 a=? b=? c=?
此文章來自奇摩知識+如有不便請留言告知
最佳解答:1/a + 1/b + 1/c = 1/8 1/a = 1/8 - 1/b - 1/c 1/a = (bc - 8b - 8c) / 8bc a = 8bc / (bc-8b-8c) Similarly, you can get: b = 8ac / (ac-8a-8c) c = 8ab / (ab-8a-8b)
其他解答:
a=16 b=32 c=64
文章標籤
全站熱搜
留言列表
